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Capacitors VERY QUICK EASY QUESTION! PLEASE HELP!

  1. Mar 19, 2008 #1
    [SOLVED] Capacitors VERY QUICK EASY QUESTION! PLEASE HELP!

    1. The problem statement, all variables and given/known data

    A parallel-plate capacitor has circular plates of 8.80 cm radius and 1.50 mm separation.
    (a) Calculate the capacitance.
     
    Last edited: Mar 19, 2008
  2. jcsd
  3. Mar 19, 2008 #2
    THE answer has to be in pF for part a)
     
  4. Mar 19, 2008 #3
    I don't know what R is, and I don't know what L is. I can assume that A is the area, but the equation your teacher gave you makes no sense to me, as the equation for a parallel plate capacitor is:

    [tex]C=\frac{k\epsilon _0A}{d}[/tex]

    For air or free space, k is about 1.

    There's also another equation:

    [tex]C=\frac{Q}{V}[/tex]
     
  5. Mar 19, 2008 #4
    Distance of separation.
    Area.
    Capacitance
    Voltage
    [tex]\epsilon_0=8.85\times10^-12 \frac{C^2}{Nm^2}[/tex]
    Q = charge
     
  6. Mar 27, 2008 #5
    1808
     
    Last edited: Mar 27, 2008
  7. Mar 27, 2008 #6
    I can't say if the answer is right or wrong without you showing any work.
     
  8. Mar 27, 2008 #7
    Looks right.
     
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