1. Mar 19, 2008

### physicsbhelp

1. The problem statement, all variables and given/known data

A parallel-plate capacitor has circular plates of 8.80 cm radius and 1.50 mm separation.
(a) Calculate the capacitance.

Last edited: Mar 19, 2008
2. Mar 19, 2008

### physicsbhelp

THE answer has to be in pF for part a)

3. Mar 19, 2008

### Snazzy

I don't know what R is, and I don't know what L is. I can assume that A is the area, but the equation your teacher gave you makes no sense to me, as the equation for a parallel plate capacitor is:

$$C=\frac{k\epsilon _0A}{d}$$

For air or free space, k is about 1.

There's also another equation:

$$C=\frac{Q}{V}$$

4. Mar 19, 2008

### Snazzy

Distance of separation.
Area.
Capacitance
Voltage
$$\epsilon_0=8.85\times10^-12 \frac{C^2}{Nm^2}$$
Q = charge

5. Mar 27, 2008

### physicsbhelp

1808

Last edited: Mar 27, 2008
6. Mar 27, 2008

### Snazzy

I can't say if the answer is right or wrong without you showing any work.

7. Mar 27, 2008

Looks right.