Car Displacement & Speed Calculation

Thread starter miamiheat5
Start date Feb 19, 2007
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Calculation Car Displacement Speed

AI Thread Summary

The car's displacement after traveling 10.0 km north and 8.0 km east is calculated to be 12.8 km at an angle of 38.7 degrees east of north. The average speed of the trip is determined to be 0.426 km/min, which converts to approximately 0.0071 m/s. The average velocity, defined as displacement over time, is still under discussion, with clarification needed on the calculation method. The total time for the trip was 30 minutes. Accurate calculations are essential for understanding displacement and velocity in physics.

Feb 19, 2007

miamiheat5

A car travels 10.0km due north, then 8.00km due east, the total trip taking 30.0 minutes. Find (a) the displacement of the car, (b) the average speed (in m/s), and (c) the average velocity (in m/s)

a) 10^2+8^2=c^2
164=c^2
c=12.8km

tanx=8/10
x=38.7 degrees

12.8km @ 38.7 degrees E of N

b) d=vt
v=d/t
v=12.8/30.0
v=0.426km/min

c) not sure

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Feb 19, 2007

chaoseverlasting

Average velocity is displacement over time taken.

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