- #1
Joshk80k
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Homework Statement
[tex] \oint \frac{dz}{z^2 + z} = 0, C: abs(z) > 1 [/tex]
Homework Equations
[tex] \oint \frac{f(z)}{z-z_0} dz = 2i\pi * f(z_0) [/tex]
The Attempt at a Solution
Under normal circumstances, I usually deal with these in the following way.
I say that F(z) = 1 (the value in the numerator) and I find the value that will make the denominator go to zero (in this case, 1 or 0).
Evaluating for F(z) = 1 and z_0 = 1, and plugging these values into the equation I provided, the answer comes out to be
[tex] 2i\pi [/tex]
Which is definitely not what the question was asking me to prove.
I am pretty sure that since we have the condition that abs(z) > 1, I am not allowed to pick the value of "1 or 0" for this problem. I'm at a loss as to what to do next.
Additionally, I was considering factoring out a z in the denominator and letting f(z) = 1/z, but I'm not sure that would help anything, or if that's even the correct way to go about doing this. If anyone could show me what to do when my values of z are restricted, I'd be very appreciative!
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