- #1

Dweirdo

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OMG second time I'm opening a thread in the wrong forum FFS!

Damn bookmarks! MODS move it please.

Not a home work question, just something i cam across and need a clarification.

Could One show me how to derive to the equation that X(cm)=int(X dm)/M

int=the deformed S of the integral(2 lazy to write in Latex XD).

X(cm)=sigma(Xi Dmi)/M

I know It's simple, But I can't imagine how sigma(Xi Dmi) becomes int(X dm),

I don't understand what it means , trying to convert it to words just doesn't work for me,so could some 1 explain that for me?

AFAIK sigma(Xi Dmi) means the mass distribution,but how does the integral takes place here?

I really need to understand the math part in physics.

Thanks a lot in advanced !

Damn bookmarks! MODS move it please.

## Homework Statement

Not a home work question, just something i cam across and need a clarification.

Could One show me how to derive to the equation that X(cm)=int(X dm)/M

int=the deformed S of the integral(2 lazy to write in Latex XD).

## Homework Equations

X(cm)=sigma(Xi Dmi)/M

## The Attempt at a Solution

I know It's simple, But I can't imagine how sigma(Xi Dmi) becomes int(X dm),

I don't understand what it means , trying to convert it to words just doesn't work for me,so could some 1 explain that for me?

AFAIK sigma(Xi Dmi) means the mass distribution,but how does the integral takes place here?

I really need to understand the math part in physics.

Thanks a lot in advanced !

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