How Does Angular Velocity Relate to Centripetal Acceleration?

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To achieve a centripetal acceleration of 3 g's at a radius of 2.5 m, the angular velocity (W) must be calculated using the formula W^2R = centripetal acceleration. By substituting the values, W was found to be approximately 3.4 radian/sec. It's important to include units in calculations to verify correctness, as acceleration is measured in m/s^2 and radius in meters. This ensures that the resulting units for W are in 1/s, confirming the calculation is accurate. The discussion emphasizes the significance of unit consistency in physics problems.
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Homework Statement


What angular velocity would cause a centripetal acceleration of 3 g's if the radius were 2.5 m?

i have a test 2moro on this stuff... yea i need to know =D thx


Homework Equations



i guess m(v^2)/r or mW^2r

The Attempt at a Solution



no idea. srry :confused:
 
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iamtrojan3 said:

Homework Equations



i guess m(v^2)/r or mW^2r

What is the W? And what do you calculate with mW^2r?
 
W is rotational velocity.. sryy for not making that clear.
(MASS)(W^2)(radius)=centripetal Force
W^2R= Centripetal Acceleration
I just plugged numbers in 29.4= W^2(2.5) and i got 3.4radian/sec for W.
this looks 2 easy... if someoen could verify please =D
 
Yes, very good, your answer is correct. But you should also write down the units, for example acceleration is in m/s^2 and radius in m. This allows you to check whether your result is correct.

For example if you calculated W as something with 1/s^2, you know you made a mistake because the unit must be 1/s (or radian/sec).
 
Last edited:
thanks tons edgardo!
 
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