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If I have a set the vent 2500 mm2; A = 2.5e-3 m^2

Cd = 0.61

Internal pressure to be 102,135 and the external pressure to be 102,140;

p = 1.21205 (at 20 C)

delta P = 5 Pa.

volume = 55 m^3q = Cd A ((2 *delta P )/p)^0.5

so q = 0.004308549 m^3/s or 0.258512945 m^3/ minIf I wanted to calculate the next internal pressure,

the mass entering the room is 0.313331 kg,

Converting this back into a pressure value,

P = m * R *T / V

P = 480 Pa. So the new internal pressure is 102135 + 480 = 101715 Pa

So the next pressure difference is 475, which causes a larger air flow and a larger difference pressure the next time. It starts to spiral out of control.

Any ideas?