Changing bounds of integration of a double integral

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SUMMARY

The discussion centers on changing the bounds of integration for a double integral involving the parabola y = x². The correct bounds are identified as y ranging from 0 to x² and x ranging from 0 to 1, which accurately describes the area to the right of the parabola, bounded by the x-axis and the line x = 1. Participants confirm that visualizing the region is crucial for correctly setting the limits of integration, leading to the correct answer of approximately 0.40.

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  • Understanding of double integrals
  • Familiarity with the concept of bounds of integration
  • Knowledge of parabolic equations, specifically y = x²
  • Ability to visualize geometric regions in the Cartesian plane
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Students and educators in calculus, mathematicians working with integrals, and anyone looking to improve their understanding of double integrals and their applications in geometry.

yopy
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Picture of the problem is listed above. I'm not sure how to switch the bounds of integration on it. Anyone here know how to go about this?

i tried doing it x^2 to 1 for y and then 0 to 1 for x but it didnt work out to be the write answer, the write answer after putting it in your calculator is about .40 ish

Normally when i do these kinds of problems i draw the bounds out, but I am not sure how these current bounds would even look.
 
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Hi yopy! :smile:

(try using the X2 tag just above the Reply box :wink:)
yopy said:
i tried doing it x^2 to 1 for y and then 0 to 1 for x but it didnt work out to be the write answer …

Well, that looks right to me …

it's just the area above the parabola y = x2

show us what you got.
 
i figured it out, the bounds turn into 0 to x^2 for respect to Y, and then 0 to 1 for respect to X

my problem was drawing the region they were integrating over. I got the right answer though, thanks.
 
tiny-tim said:
Hi yopy! :smile:

(try using the X2 tag just above the Reply box :wink:)


Well, that looks right to me …

it's just the area above the parabola y = x2


I don't think so. The limits of integration in the original problem indicate that the region is to the right of the parabola, not above it. The region is bounded by the parabola, the x-axis, and the line x = 1. Yopy's revised limits of integration describe this region.
 
oops!

Mark44 said:
I don't think so. The limits of integration in the original problem indicate that the region is to the right of the parabola, not above it. The region is bounded by the parabola, the x-axis, and the line x = 1. Yopy's revised limits of integration describe this region.

oops! :redface: i should have drawn it! :rolleyes:

thanks Mark! :smile:
 

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