Changing complex numbers in form a+bi

AI Thread Summary
The discussion revolves around solving the complex number problem using polar and exponential forms. Participants emphasize the efficiency of converting to exponential form before raising it to a power, as it simplifies calculations significantly. The use of de Moivre's Theorem is highlighted as a helpful method for dealing with powers of complex numbers. There is some confusion regarding terminology, particularly the meaning of "2pier," which is clarified as referring to radians. Ultimately, the consensus is that using Euler's formula streamlines the process of converting back to the a+bi form.
ME_student
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Homework Statement


Here is the problem: (\sqrt{}6(cos(3pie/16)+i sin(3pie/16)))^4

Homework Equations



After 360*=2pier Do you add 2pier to the next degree which would be 30*=pie/6?

The Attempt at a Solution

 
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In situations such as these, it is usually easiest to convert to the exponential form and solve from there, then convert back to a+bi form.
 
ME_student said:
After 360*=2pier Do you add 2pier to the next degree which would be 30*=pie/6?
What do you mean by this? By "2pier" do you mean ##2\pi## radians or ##2\pi r##, the circumference of a circle? What is "the next degree"? After 360 degrees, the next degree is 361 degrees, no?
 
The greek letter \pi is just spelled as "pi". It is not the same as the dish.
 
vela said:
What do you mean by this? By "2pier" do you mean ##2\pi## radians or ##2\pi r##, the circumference of a circle? What is "the next degree"? After 360 degrees, the next degree is 361 degrees, no?

Sorry, I couldn't find the 2 "pie" r.

No worry guys I figured it out. Wish I could post pictures... I would show you how I solved it.

EDIT: Sweet I can post pics now!
 
Here is the problem
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Per daveb, I too think it would be much easier to convert to polar form first and then convert back. The reason is that the exponential lends itself to being raised to a power much more easily than the rectangular form.

What you get is

(\sqrt{6} e^{3\pi i/16})^4 = 36 e^{3\pi i/4}

This is what you got, after all, but you can do it in one line as opposed to resorting to a bunch of trig identities to square the rectangular form.
 
Apologies for the quality of the pictures...
 
Look up de Moivre's Theorem. It'll narrow down the tedious computation with multplying it out.
 
  • #10
$$(cos(x)+i~sin(x))^{n} = cos(nx)+i~sin(nx)$$
 
  • #11
Whoa... I was a member while taking trig, crazy!
 
  • #12
So much easier when using Euler's formula. I can do it in my head rather quickly.
 
  • #13
2milehi said:
So much easier when using Euler's formula. I can do it in my head rather quickly.

Good for you.
 
  • #14
Just sayin' - if you recognize this

c9f2055dadfb49853eff822a453d9ceb.png


then the problem become easy to do. There are plenty of ways to skin the cat with this problem.
 
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