- #1
UrbanXrisis
- 1,196
- 1
In a right triangle with sides x,y,z, the theta between leg z and leg y is increasing at a constant rate of 3 rad/min. What is the rate at which x is increasing in units per minute when x equals 3 units and z is 5 units.
so the triangle is basically a 3,4,5 triangle. The theta is between the leg 5 and 4. Leg 4 does not chage since it's the base. To set up a changing rates problem, I did:
[tex]tan\theta = \frac{O}{A}[/tex]
[tex]4tan \frac{d \theta}{dt} = \frac{dx}{dt}[/tex]
[tex]\theta=-0.570 rad/min[/tex]
I think there is something wrong with this but I'm not sure why the theta is negative.
so the triangle is basically a 3,4,5 triangle. The theta is between the leg 5 and 4. Leg 4 does not chage since it's the base. To set up a changing rates problem, I did:
[tex]tan\theta = \frac{O}{A}[/tex]
[tex]4tan \frac{d \theta}{dt} = \frac{dx}{dt}[/tex]
[tex]\theta=-0.570 rad/min[/tex]
I think there is something wrong with this but I'm not sure why the theta is negative.