- #1
notmetalenough
- 11
- 0
I'm doing my first electromag homework so there will probably be a few more of these.
Two small beads having positive charges 19q and q are fixed at the opposite ends of a horizontal insulating rod extending from the origin (the location of the larger charge) to the point x = d. As in the figure below, a third small charged bead is free to slide on the rod.
So I figure that
F = ((k * 19q Q)/ x^2) - (k* q * Q)/(d-x)^2)
so 19/x^2 = 1/(d-x)^2
d-x = x / sqrt(19)
d = x + x/sqrt(19)
= x * (1+sqrt(19))/sqrt(19)
so x = d * (sqrt(19))/(1 + sqrt(19))
which would be about 0.81339
apparently it's the wrong answer. Can anyone tell me why, or where I went wrong?
Two small beads having positive charges 19q and q are fixed at the opposite ends of a horizontal insulating rod extending from the origin (the location of the larger charge) to the point x = d. As in the figure below, a third small charged bead is free to slide on the rod.
So I figure that
F = ((k * 19q Q)/ x^2) - (k* q * Q)/(d-x)^2)
so 19/x^2 = 1/(d-x)^2
d-x = x / sqrt(19)
d = x + x/sqrt(19)
= x * (1+sqrt(19))/sqrt(19)
so x = d * (sqrt(19))/(1 + sqrt(19))
which would be about 0.81339
apparently it's the wrong answer. Can anyone tell me why, or where I went wrong?