Defibrillation[/B] is a common treatment for life-threatening cardiac arrhythmias and ventricular fibrillation. The defibrillator applies a current across the heart (shown by the red arrows in the image below) for a short time (a few milliseconds), disrupting the arrhythmia and hopefully allowing the normal heartbeat to resume. The electric current is supplied by a device called a defibrillator (shown on the left in the image below).
The defibrillator uses a capacitor to store the charge that will be delivered in the current. The capacitor forms part of an RC-circuit, as shown in the diagram below:
Calculate the amount of charge stored on the capacitor after the capacitor has been charging for 1.10 s.
- The capacitance of the capacitor is 28.1 μF and the resistance of the resistor is 20.4 kΩ.
- Time constant of the RC circuit within the defibrillator = 0.573 s
- The amount of charge stored on the capacitor when the capacitor is fully charged to 2.75 kV = 0.0773 C
The Attempt at a Solution
C = T/R
= 5.39x10^-5 F was not correct
Not sure where to go for this question as I don't understand the following equation;
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