Charged ball attached to a charged sheet

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A small nonconducting ball with a mass of 0.80 mg and a charge of 2.2 x 10^-8 C is suspended at a 45° angle from a charged sheet. The tension in the thread creates equal x and y force components, leading to the conclusion that the electric force equals the weight of the ball. The electric field is derived from the surface charge density using the formula E = σ / (2ε). The calculated surface charge density of 6.3169 µC/m² was questioned, particularly regarding the use of the ball's charge in the calculations. Clarification on the figure referenced in the problem was also requested.
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Homework Statement


In Figure 23-43, a small, nonconducting ball of mass m = 0.80 mg and charge q = 2.2 multiplied by 10-8 C (distributed uniformly through its volume) hangs from an insulating thread that makes an angle θ = 45° with a vertical, uniformly charged nonconducting sheet. Considering the gravitational force of the ball and assuming that the sheet extends far vertically and into and out of the page, calculate the surface charge density σ of the sheet.

Homework Equations


E = surface charge density / 2epsilon


The Attempt at a Solution


Recognizing that b/c the angle of the thread is 45, the x and y components of the force of tension are equal, and therefore the electric force pushing the ball away from the wall is equal to Tx is equal to Ty is equal to weight. So F = mg.

E = F / q
F = mg
E = surface charge density / 2epsilon
mg / q = surface charge density / 2epsilon
surface charge density = mg2epsilon / q

I know m, g, and q.
I plug it in and get 6.3169 microC/m^2

But this isn't the answer, and I thought I was using the formula's correctly. Am I using the charge of the ball correctly? It seems like that would be the first place I would mess up.

Thanks for looking at this.
 
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Can I see the figure?
 
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