Charged Metallic Sphere Touching Spherical Shell From Inside

AI Thread Summary
A metallic sphere with a charge of 450 nC is connected to an uncharged metallic spherical shell, leading to a discussion on how charge distributes between them. For part (i), the charge distribution can be calculated using the principle of equal potential, resulting in various possible outcomes based on the options provided. In part (ii), the scenario changes as the charged sphere touches the inner surface of the shell, raising questions about charge distribution and electric fields inside conductors. The consensus emphasizes that when the two conductors touch, they act as a single conductor, and the charge resides on the outer surface, not affecting the inner surface. The discussion highlights the importance of understanding electric fields and potential in conductive materials.
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Homework Statement


(From Physics for Scientists and Engineers, 7E, Serway-Jewett Chapter 25 Q11)

(i) A metallic sphere A of radius 1 cm is several centimeters away from a metallic spherical shell B of radius 2 cm. Charge 450 nC is placed on A, with no charge on B or anywhere nearby. Next, the two objects are joined by a long, thin, metallic wire (as shown in Fig. 25.20), and finally the wire is removed. How is the charge shared between A and B?

(a) 0 on A, 450 nC on B
(b) 50 nC on A and 400 nC on B, with equal volume charge densities
(c) 90 nC on A and 360 nC on B, with equal surface charge densities
(d) 150 nC on A and 300 nC on B
(e) 225 nC on A and 225 nC on B
(f) 450 nC on A and 0 on B
(g) in some other predictable way
(h) in some unpredictable way

(ii) A metallic sphere A of radius 1 cm with charge 450 nC hangs on an insulating thread inside an uncharged thin metallic spherical shell B of radius 2 cm. Next, A is made temporarily to touch the inner surface of B. How is the charge then shared between them? Choose from the same possibilities. Arnold Arons, the only physics teacher yet to have his picture on the cover of Time magazine, suggested the idea for this question.


Homework Equations



- V=kq/r (used in part (i))

Possibly relevant :
- V=k ∫dq/r,
- V=-∫E°dl,


The Attempt at a Solution



For part (i) I was able to reach an answer using V1 = V2, assuming conservation of charge:

kq1/r1 = kq2/r2;
where q1+q2=450 nC

However for part (ii) I am pretty lost. Ideas I have tried were a similar solution to part (i), a cavity within a conductor (suggesting E inside the spherical shell should be 0), or the fact that net electric charge of a conductor is on its surface.

My attempts were unfruitful. A similar solution to (i) doesn't make all that sense to me, as I feel like they become the same thing when they touch one another (sounds romantic). Cavity within a conductor (which I literally just pulled off the textbook as I was looking for an idea to help me solve it) kind of seemed to be helpful, however, I might be misinterpreting it to make my case here. The net electric charge on surface idea also seems to lose ground when I think about the inside sphere's surface being part of the "sphere inside shell" object's surface, therefore having charge on it.

Thank you very much for your help and time.
 
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or the fact that net electric charge of a conductor is on its surface.
That is sufficient. When they touch, you can consider them as a single conductor. Where is the whole charge? It is important that the outer sphere has no hole here.
 
Thank you very much for the response. The whole charge is on the surface, but doesn't that include the inner surface and thus the surface of the inner sphere? Why does it lose the surface charge when it goes back to its original position? Thanks again.
 
An inner surface with charge would lead to a field inside. That cannot happen - inner surfaces are always regions of constant potential, and there is nowhere the electric field lines could end (no additional charges separated from your object).
 
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