Charged particle and Earth's magnetic field at equator question

AI Thread Summary
A charged particle interacting with the Earth's magnetic field at the equator primarily experiences a change in direction due to the Lorentz Force Law. The discussion reveals confusion about whether the particle's speed is affected, with participants concluding that the speed remains constant while the direction changes. The equatorial position is highlighted as a factor influencing the interaction, emphasizing the perpendicular relationship between the magnetic field and the particle's velocity. The right-hand rule is referenced to further clarify the direction of the force acting on the particle. Ultimately, the consensus leans towards the conclusion that the particle's direction changes without affecting its speed.
bmac
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Homework Statement



Stumped on this one.
A charged particle hurles through space creatings its own magnetic field, if it strikes the Earth's equator, the 2 magnetic fields interact and...

a) do not affect the particles direction
b) change the particles speed but not direction
c) change the particles speed and direction
d) change the particles direction
e) bounce it back in the direction it came from.

The Attempt at a Solution



I chose b but this is wrong. so I am thinking it's c...
 
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Thank you for replying I appreciate it.

Ok from your link after reviewing I would say...

d) change the particles direction

but I don't see how this also wouldn't affect speed as well.
 
I'd say that shows some understanding.

Good luck.
 
Yeah I am trying to understand it, a lot of this seems a little advanced for 9th grade science. Definitely not my best class.

I am going with c then, I think the fact that it was the equator confused me a little bit as far as direction goes.
 
bmac said:
I am going with c then, I think the fact that it was the equator confused me a little bit as far as direction goes.

This would be my thinking.

The force of the B field is the vector cross product of the field and the particle's velocity. The idea of it being at the equator is to suggest that the B field is ⊥ to its radial direction from the sun. So with B ⊥ V and hence the F ⊥ V (the vector cross product does that), I would say that the force acts to deflect the particle. Since the Force is ⊥ to the direction of motion it isn't doing any work on the particle and hence its kinetic energy remains the same.
 
Ok since the kinetic energy would be the same then i was right earlier with just the direction only being changed? using the right hand rule
 
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