Charges at the corners of a square.

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    Charges Square
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The discussion focuses on calculating the electric field experienced by charge q located at a corner of a square with four positive charges at each corner. The user attempts to derive the electric field components using the formula Ex = [q1*q2/(4*∏*εo*a^2)]cosθ and Ey = [q1*q2/(4*∏*εo*a^2)]sinθ, but expresses confusion over the lack of specific values. They realize a mistake in their calculations regarding the denominators after consulting an external resource. The conversation emphasizes the importance of correctly applying the distance squared in the equations. Overall, the user is working through the complexities of electric field calculations in a multi-charge system.
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Homework Statement


Four positive charges are located on the corners of a square of side-length a.
The charges are A=4, B=2, C=8
4q----a----q
|------------|
a-----------a
|------------|
2q----a----8q

Determine the magnitude and direction of the electric field experienced by charge q in terms of q, a, and ke.

Homework Equations


Ex = [q1*q2/(4*∏*εo*a^2)]cosθ
Ey = [q1*q2/(4*∏*εo*a^2)]sinθ

The Attempt at a Solution



Ex = 4keq2/a^2 + 2keq2/[(2a2)^.5]cos45
Ey = [2keq2/(a*21/2)]sin45 + 8keq2/a2

I know I have to sum up the x components from A->q and B->q for the x component of the vector, and then sum up the y components from B ->q and C->q for the y component and then use the pythagorean theorum to find the magnitude. For the direction I have to take the tangent of the y-component/x-component. I am just confused because there aren't any values given. Would the above be correct?
 
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msemsey said:
Ex = 4keq2/a^2 + 2keq2/[(2a2)^.5]cos45
Ey = [2keq2/(a*21/2)]sin45 + 8keq2/a2
Check the expressions for the denominators.
 
TSny said:
Check the expressions for the denominators.

I just went on fearofphysics.com (lifesaver) and have realized my error. I had the distance squared for one fraction, but not the other one. Thank you very much.

Edit: It WOULD be one of those errors.
 
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