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Charging potential vs time graph.

  1. Apr 30, 2009 #1

    dE_logics

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    Why don't we simply take t as x? why is it t?

    Where is the time constant.

    If you're looking at a question mark instead of the symbol "tau"...you know its tau.
     
    Last edited: May 1, 2009
    dE_logics, Apr 30, 2009
  2. jcsd
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  3. May 1, 2009 #2

    Andrew Mason

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    You might get an answer if you explained what the question is.

    AM
     
    Andrew Mason, May 1, 2009
  4. May 1, 2009 #3

    dE_logics

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    On one axis we have the charging current/voltage, while on the other instead of time (t) we have t ...why?


    And yeah...latex is still giving problems?...I think I got a cache problem.
     
    dE_logics, May 1, 2009
  5. May 1, 2009 #4

    jtbell

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    This picture shows what I'm seeing:
     

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    jtbell, May 1, 2009
  6. May 1, 2009 #5

    dE_logics

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    Actually I'm on linux, and so this website seems MS friendly.

    So that 'tau' seems like a matrix in windows.

    So if you encounter any sorta weird symbols, take it as 'tau' or time constant.
     
    dE_logics, May 1, 2009
  7. May 2, 2009 #6

    jtbell

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    So are you trying to write [itex]t / \tau[/itex]?
     
    jtbell, May 2, 2009
  8. May 2, 2009 #7

    dE_logics

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    ITs t*tau not t/tau.
     
    dE_logics, May 2, 2009
  9. May 2, 2009 #8

    dE_logics

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    Latex just started working for me!

    [tex]t \tau[/tex]...this is what I mean.
     
    Last edited: May 2, 2009
    dE_logics, May 2, 2009
  10. May 3, 2009 #9

    jtbell

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    :confused:

    I've seen many capacitor charging/discharging graphs that use [itex]t / \tau[/itex] on one of the axes, but never one that uses [itex]t \tau[/itex]. Are you sure the [itex]\tau[/itex] isn't a subscript, i.e. [itex]t_{\tau}[/itex]?
     
    jtbell, May 3, 2009
  11. May 3, 2009 #10

    dE_logics

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    dE_logics, May 3, 2009
  12. May 3, 2009 #11

    jtbell

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    Are you referring to graphs like this one?

    The horizontal scale markings indicate [itex]t = \tau[/itex], [itex]t = 2 \tau[/itex], [itex]t = 3 \tau[/itex], etc. This means the same thing as [itex]t / \tau = 1[/itex], [itex]t / \tau = 2[/itex], [itex]t / \tau = 3[/itex], etc.

    The 1, 2, 3, etc. are not t's. t and [itex]\tau[/itex] both have units of time, so the numbers are dimensionless.
     
    jtbell, May 3, 2009
  13. May 3, 2009 #12

    dE_logics

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    Yeah...the same thing.

    So why did this [tex]\tau[/tex] stuff pop by?...why not simply use time?
     
    dE_logics, May 3, 2009
  14. May 3, 2009 #13

    Born2bwire

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    Normalization, the time constant will vary between different values of R and C but as long as you plot the time axis in terms of the time constant then the plots will all be the same (barring differences in the magnitude of the initial voltage).
     
    Born2bwire, May 3, 2009
  15. May 3, 2009 #14

    dE_logics

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    Oh...you mean to maintain the nature of the graph...right?
     
    dE_logics, May 3, 2009
  16. May 4, 2009 #15

    Born2bwire

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    Yeah. Plotting in units of time constants allows the graph to be scale invariant with respect to the R and C of the circuit. It's the same reason why when we plot graphs of waves and such we use wavelengths as our units of space. It automatically scales the plots in such a way that the information of interest is readily seen.
     
    Born2bwire, May 4, 2009
  17. May 4, 2009 #16

    dE_logics

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    Humm...ok, thanks!
     
    dE_logics, May 4, 2009
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