Calculate Reactant Concentration from Chemical Equilibrium Moles

In summary, the conversation revolves around finding the concentration of CO in an equilibrium reaction. The initial answer of 8000 mol/L is deemed absurd and the conversation discusses the possibility of an error in the provided equilibrium constant and the use of physical units. It is suggested that the concentration of CO is actually 2.26M and further discussion is had about the feasibility of this concentration in an industrial setting. The conversation also highlights the importance of recognizing when an answer is incorrect.
  • #1
ohms law
70
0
If someone could check my work on this, I'd appreciate it:
ScreenHunter_04 Oct. 18 13.36.jpg


Thanks!
 
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  • #2
Number fits the data given, but is an insult to the logic - 8000M concentration doesn't make sense.
 
  • #3
That's what made me question the answer myself. 8000 mol/L sounds ridiculous.
I quadruple checked the work though, and put the 8.8x10^3 value back into the original equilibrium expression, and it does come out to 1.60773043 × 10^(-2) (2 s.f. in that, as well), so I guess that it's correct. *shrug*
 
  • #4
Well at least congratulations on realizing the answer was ridiculous, a criterion and useful habit not every student realizes and puts to use.

The reciprocal of 8,000 is, I don't know if right, but not so ridiculous.

The other thing that you needed to recognize was that you have quoted (or misquoted) an equilibrium constant without any units. But an equilibrium constant for that reaction should have units like M2 or M-2 and if you are given that - I very much doubt you weren't - it is informative about which way up you should be writing your equation. ;)
 
  • #5
@epenguin, it's an equilibrium constant (K), not a rate constant (k).
:)

One thing about this reaction that someone at school mentioned was that in real life it takes place in a pressurized system, so 8000 Molarity CO isn't that ridiculous if we're talking about a system at 100 atmospheres. Supposedly they use catalysts as well (which, I know, shouldn't actually affect concentrations, but I bring it up just to drive home the point that this problem isn't providing all of the information about the reaction process).
 
  • #6
Check what would be the density of 8000 M CO. Compare that to the density of osmium.
 
  • #7
ohms law said:
@epenguin, it's an equilibrium constant (K), not a rate constant (k).
:)

Think again about that though. If I had thought it was a rate constant I would have been looking for time as well as possibly molarity in the dimensions, e.g sec-1 or M-1sec-1 etc.

Only if you have the same number of molecules on both sides of the reaction as in A ⇔ B,
or A + B ⇔ C + D , which is common but not your case, is the molar dimension of an equilibrium constant zero, you could call it dimensionless.

So that constant should not have been given you without dimensions. Can you trace to where you got it from? If not does the constant upside-down give results that are reasonable by any way you can check?
 
  • #8
Gen chem, so all equilibrium constants are dimensionless. Period.
You're talking about stuff in physical chem. I have enough on my plate without adding unnecessary complexity, thanks.
:)

Here's a more complete explanation, though:
ScreenHunter_12 Oct. 29 13.46.jpg


Besides, this problem was about finding the concentration of one of the reactants. The units work out to Molarity^1, which makes perfect sense, so... what's the problem?

To Borek: ok, fine. This is an actual reaction that is used in industry every day, so how about you tell us all what the "real" concentration is supposed to be?
 
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  • #9
ohms law said:
Gen chem, so all equilibrium constants are dimensionless. Period.
You're talking about stuff in physical chem. I have enough on my plate without adding unnecessary complexity, thanks.
:)

Here's a more complete explanation, though:
View attachment 52439

Besides, this problem was about finding the concentration of one of the reactants. The units work out to Molarity^1, which makes perfect sense, so... what's the problem?

I could not come back earlier, for one thing I could not see your inserts on my device.

Maybe I am out of date then but I remember we always used physical units for equilibrium constants in biochemistry and biophysics as far as I remember. We seem to be finding that a disadvantage of the convention you quote is that we cannot do or check the calculation so I wouldn't agree it has simplified life. Unfortunately I could not find this equilibrium constant in a Wiki search.

You are following the implicit convention of your quoted text K = (product of concs. on right)/(product concs. on left) , then I get the same as your calculation
[CO] = 141.54/K which gives result agreeing with your absurd one.

I wondered if the convention were otherwise and K = 1/1.6*10-2. Then I get a more reasonable sounding 2.26M for the CO.

But still that is about 50 atm. In a flask?. The other concentrations are small fractions of atmospheric. Quite far from a reasonable concentration for an industrial operation and even a laboratory experiment.

All the numbers sound rather screwy, I wonder if anything has been mistranscribed at any stage. Unless your papers are marked by computers you get credit for showing you know when an answer is somehow wrong. I hope you will come back and tell us more if this is class work that is marked or discussed.

Edit: corrected a key typo :smile:
 
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1. How do I calculate the reactant concentration from chemical equilibrium moles?

To calculate the reactant concentration from chemical equilibrium moles, you will need to know the equilibrium constant (K) for the reaction and the initial concentrations of the reactants. Then, you can use the formula [Reactant] = [Initial Reactant] - (x * [Stoichiometric Coefficient]), where x is the number of moles consumed or produced in the reaction. This will give you the equilibrium concentration of the reactant.

2. What is the equilibrium constant (K) for a reaction?

The equilibrium constant (K) is a value that represents the ratio of the concentrations of products to reactants at equilibrium for a given reaction. It is calculated using the formula K = [Product]n / [Reactant]m, where n and m are the coefficients in the balanced chemical equation. The value of K is dependent on temperature and is a measure of the extent of the reaction at equilibrium.

3. How do I determine the initial concentrations of the reactants?

The initial concentrations of the reactants can be determined by using the known amounts of each reactant and the volume of the solution. If the reaction takes place in a closed system, the initial concentration can be calculated using the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.

4. Can I calculate the reactant concentration at any point during the reaction?

Yes, you can calculate the reactant concentration at any point during the reaction as long as you know the initial concentrations, the equilibrium constant, and the number of moles consumed or produced at that point. Keep in mind that the equilibrium concentration may change as the reaction progresses, so the calculation will only be accurate for that specific point in time.

5. How does the concentration of the reactant affect the equilibrium constant?

The concentration of the reactant does not directly affect the equilibrium constant. The value of K is determined by the temperature and the nature of the reaction, not the initial concentrations of the reactants. However, the concentration of the reactant can indirectly affect the value of K if it impacts the rate of the reaction and the time it takes to reach equilibrium.

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