What Pressure Should You Fill the Acetylene Tank For Equal Gas Consumption?

AI Thread Summary
To ensure equal gas consumption in welding, the acetylene tank must be filled to a specific pressure based on the oxygen tank's pressure and volume. Given a 6.50 L oxygen tank filled to 105 atm, the acetylene tank's pressure can be calculated using the ideal gas law and the stoichiometric ratio from the combustion reaction. The user is uncertain about how to determine temperature for these calculations, assuming room temperature for simplicity. Applying Boyle's Law and the ideal gas law will help find the necessary pressure for the acetylene tank. Accurate calculations will ensure both gases deplete simultaneously during use.
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Homework Statement



Acetylene torches are used for welding. These torches use a mixture of acetylene gas, C_2H_2, and oxygen gas, O_2 to produce the following combustion reaction:

2C_2H_2(g) + 5O_2(g) --> 4CO_2(g) + 2H_2O(g)

Imagine that you have a 6.50 L gas tank and a 4.50 L gas tank. You need to fill one tank with oxygen and the other with acetylene to use in conjunction with your welding torch. If you fill the larger tank with oxygen to a pressure of 105 atm, to what pressure should you fill the acetylene tank to ensure that you run out of each gas at the same time?


Homework Equations



Boyle's Law: P_1V_1 = P_2V_2
Charles Law: V_1/T_1 = V_1/T_1
Ideal Gas Law: PV = nRT

The Attempt at a Solution


Okay, I think that I have to find temperature because then I would be able to sub that into PV = nRT to find the number of moles for oxygen and then using mole ratio I can find the moles of acetylene and then sub that into the ideal gas law to find the pressure for acetylene. But I'm not exactly sure how to calculate temperature. Any help is greatly appreciated!
 
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Assume room temperature.
 
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