Chemistry: Prediction of producs

AI Thread Summary
The discussion focuses on predicting products for two chemical reactions involving sodium nitrate, ammonium sulfate, iron (III) acetate, and other compounds. Participants explore the formation of precipitates, with one suggesting that iron and sulfate will create iron (III) sulfate as a solid product, while ammonium acetate acts as a spectator ion. For the second reaction, the formation of strontium phosphate is identified as the insoluble salt, with a consensus that the other reactants remain soluble. The importance of recognizing spectator ions and applying solubility rules is emphasized throughout the conversation. Overall, the discussion highlights the challenges of predicting products and balancing equations in chemistry.
markelmarcel
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Homework Statement


Predict products (and then write formula unit, total ionic unit & net ionic equations)1. Sodium Nitrate, Ammonium sulfate and Iron (III) acetate.

2. Na3PO4 + RbClO3 + Sr(NO3)2

Homework Equations



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The Attempt at a Solution



1. NaNO3 + (NH4)2S + Fe(CH3CO2)3
I just don't know how to decide what parts will be "spectator ions" and how the 3 products will work out... I know it deals with acids and bases, but my prof went through it really fast and I tried reading our textbook but it didn't help very much with the 3 reactants, and he went out of town for a conference so I couldn't ask him for help...

I think that Fe and S will come together to make a precipitate which would be Fe2S3 and then I'm assuming that the NH4CH3CO2 would then combine together, leaving the NaNO3 as the spectator ions?
 
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Sulfate or sulfide? Sulfide precipitation is a good idea. Similar approach will work for the second question - just think, what combination of ions will produce something insoluble. And don't overdo - ammonium acetate will be just a spectator.

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Borek said:
Sulfate or sulfide? Sulfide precipitation is a good idea.


ah, touche! it is sulfate- don't know why when i typed it out i made it into sulfide. i was doing my own chemistry ;)
 
Ok so for the first one I got...

NaNO3 + 3(NH4)2SO4 + 2Fe(CH3CO2)3 \rightarrow Fe2(SO4)3 [/SUB](s) + 6NH4CH3CO2

When I looked up what I had for my solubility rules I found
Na3PO4, RbClO3 and Sr(NO3)2 to all be soluble... So where do I go from here? Randomly place things together??
 
Iron (III) sulfide is insoluble, but sulfate is soluble. No reaction if you ask me.

In the second question one of the combinations of cation and anion give insoluble salt.

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Ok I'm still working on balancing but for the second I'm assuming the insoluble salt has to be Sr3(PO4)2

Because PO4 is insoluble, as is Sr (with it being a group II cation).
 
markelmarcel said:
Ok I'm still working on balancing but for the second I'm assuming the insoluble salt has to be Sr3(PO4)2

Like calcium and barium phosphates and sulfates.

Because PO4 is insoluble, as is Sr (with it being a group II cation).

No such thing as insoluble PO4 - it is PO43- and it never exists without counterion.

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