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Circle Geometry

  • Thread starter Lukybear
  • Start date
  • #1
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ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N.

Show that ME = MC
 

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  • #2
berkeman
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ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N.

Show that ME = MC
What are your thoughts on how to proceed?
 
  • #3
8
0
Nvm, Ive found solution. Thxs.
 

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