Circuit analsysis problem. Simple

  • Context: Engineering 
  • Thread starter Thread starter harrisiqbal
  • Start date Start date
  • Tags Tags
    Circuit
Click For Summary
SUMMARY

The discussion focuses on solving a circuit analysis problem involving a current source in parallel with a resistor. The device is connected to a 5V voltage source, resulting in a current of 0.93A, and then to a 4A current source, leading to a voltage of -34V. The user applies Kirchhoff's Current Law (KCL) and the Current Divider Rule to derive expressions for the internal resistance and current through the resistor. The final goal is to determine the voltage v3 when a 3Ω resistor is connected to the device.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with the Current Divider Rule
  • Basic knowledge of Ohm's Law (V = iR)
  • Ability to analyze circuit diagrams
NEXT STEPS
  • Study the application of Kirchhoff's Voltage Law (KVL) in circuit analysis
  • Learn about the implications of ideal versus real voltage sources
  • Explore the concept of equivalent resistance in parallel circuits
  • Investigate advanced circuit analysis techniques such as Thevenin's and Norton's theorems
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in circuit analysis and troubleshooting.

harrisiqbal
Messages
14
Reaction score
0

Homework Statement



A device can be modeled using a current source in
parallel with a resistor. This device was connected to
a 5[V] voltage source, as shown in Figure P2.3a), and
a current i5 of 0.93[A] resulted. The same device was
then connected to a 4[A] current source as shown in
Figure P2.3b), and a voltage v4 of –34[V] resulted.
Find the voltage v3 if a 3[Ω] resistor, as shown
in Figure P2.3c), is connected to the same device.

Homework Equations



V = iR, KCL, KVL, Sign Conventions

The Attempt at a Solution



[Freaking session expired and I lost whatever I wrote.. writing it again grrrrrr]

Link to picture of diagram:
http://www.mediafire.com/imageview.php?quickkey=lzuqgmqmitk&thumb=6

I define the device as the following:

-----------------
[ ]
[ ]
Current Source Resistor
[ ]
[ ]
------------------

I connect this device to a 5 Volts voltage source for part a. And Apply KCL to get i2-i1 = 0.93 Amps. i2 is the current going through resistor, and i1 is the current by current source.

I move on to part b, and get equations [ probably the wrong ones ], but now I can't use anything from part a because the values would be different correct?

So I don't really understand how to solve this problem...

Help would be appreciated!____________________________________________________

***Update***:
Okay I understand it a bit better. For part a I use Kirchhoffs current law to find an expression for the current going through internal resistor. i2 = i1-0.93

I get an expression for Internal resistance: R = (V1 / i2) V1 is the 5 Volt power source in Part a.

Going into part b.

KCL law to get -i2 - i3 = 0 [ i3 is the given current source 4 Amps in part b]

so i2 = -4 amps

Voltage is given and current is i2. resistance can be calculated to be 8.5 Ohms.

Part c:

Current Divider Rule:

lets me find i2[ which will be different because Resistor was added]

i2= -.396 Amps

V3____________________________
I have another QUICK question unrelated to the above problem.

If a question states that there is a device that is modeled using an ideal voltage source in series with a resistance. And that device is connected to a voltage source in the schematic. Then there will be TWO Voltage sources CORRECT? One inside the device and one that the device is connected to?
 
Last edited:
Physics news on Phys.org
harrisiqbal said:
I have another QUICK question unrelated to the above problem.

If a question states that there is a device that is modeled using an ideal voltage source in series with a resistance. And that device is connected to a voltage source in the schematic. Then there will be TWO Voltage sources CORRECT? One inside the device and one that the device is connected to?

Correct. However, the first one you mention sounds like they are modeling a real voltage source as an ideal voltage source in series with its output resistance. The second voltage source might not have been expanded yet into its ideal voltage source and series output resistance, or they may just be assuming its an ideal voltage source. You'll have to figure that out from the context of the problem.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 26 ·
Replies
26
Views
3K
Replies
15
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K