Engineering Circuit Analysis using KVL and KCL

[syntha]

Homework Statement

All variables are given by the circuit unless otherwise stated

a) Derive an expression for the ratio (Vo/Vs)

Homework Equations

KCL and KVL equations

The Attempt at a Solution

Rs1=2.55kΩ
-Vs+ .05Vo +(2.5kΩ/2.55kΩ)Vp = 0 where,

Vs = .05Vo + (2.5kΩ/2.55kΩ)Vp for the left circuit.

Then for the right circuit:

Rs2= 3.70kΩ where

.08Vp=iRs

i= .08Vp/3.70kΩ, so

Vo = iR
=(.08Vp/3.7kΩ)*20kΩ, solving for Vp gives me

Vp= Vo/.432 I then substituted this into my Vs equation and solved for (Vo/Vs) and was given a ratio of .432.

Now I am not sure if my approach to this problem is right but i think the logic in going this way seems right to me. Any help or criticism would be greatly appreciated.

 

[gneill]

The 0.08Vp source is a current source. So Vo = -0.08Vp*Rs2 ...(note the direction of current flow implied by the source).

 

[syntha]

Yea I realized that its actually a current source and was able to solve the problem, my initial approach was totally off.