Circuit Elements: Battery, Resistors & Capacitor Charge 195μs Post Switch Open

AI Thread Summary
The discussion focuses on a circuit with three resistors and a capacitor connected to a battery, analyzing the charge on the capacitor 195 μs after the switch is opened. Participants clarify that the capacitor is fully charged initially, but the voltage across it after the switch opens is determined by the series combination of R2 and R3, not the battery voltage. The equation used for calculating the charge, Qmax(1-e^(t/CR)), is debated, with emphasis on the need to consider the correct resistance and voltage across the capacitor. It is suggested to use the Thevenin equivalent for the resistors to simplify the analysis. The conversation highlights the complexities of capacitor discharge in circuits with multiple resistors.
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Three resistors and a capacitor are in a circuit with a battery:
R1 = 23 Ω
R2 = 13 Ω
R3 = 15 Ω
C = 6.2 µF
V = 17 V
The switch has been closed for a long time. What will the charge be on the capacitor 195 μs after the switch is opened?

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WHat are your thoughts on the matter? Is this a charging or discharging capacitor 195 μs after the switch is opened? What are the relevant equations to describe this?
 
ok well the capacitor is fully charged, so the voltage of the capacitor is the same as the battery, from there i can find the max charge. then i used the equation Qmax(1-e^(t/CR))
where i used 28 for the resistance. but that's not giving me the right answer
 
Try again. The voltage across the capacitor is the same as across the series combination R2+R3. That's not the voltage across the battery. What is it?
 
kuruman said:
Try again. The voltage across the capacitor is the same as across the series combination R2+R3. That's not the voltage across the battery. What is it?

That's not the only problem. The current through C is not the current through either R1 or R2+R3 so you can't use those in Qmax(1-e^(t/CR) either.

I recommend replacing V, R1, R2 and R3 with their Thevenin equivalent.
 
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