Circuit with 2 loops, find the current in one of the loops

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SUMMARY

The discussion focuses on calculating the current I1 through resistor R1 in a circuit with a battery and four resistors. The circuit has a voltage of 19 V, with resistances of R1 = 12 Ω, R2 = 2 Ω, R3 = 15 Ω, and R4 = 2 Ω. The user initially calculated the total current as 2.47 A but incorrectly derived the current in the first loop as 2.03 A. The correct approach involves using the voltage across the resistors and applying Ohm's Law (I = V/R) accurately to find the current through each resistor.

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Homework Statement


A circuit composed of one battery and four resistors is arranged as shown in the attached pic.

E = 19 V

R1 = 12 W
R2 = 2 W
R3 = 15 W
R4 = 2 W


Calculate the current I1 through R1?




Homework Equations


V=IR (obviously)



The Attempt at a Solution



first i got the net current in this circuit by doing the following..
i summed resistors in series to get 14ohm on first loop and 17ohm on second loop.
then i applied resistance in parallel rule :
Req = (1/R1) + (1/R2)
= 7.69ohm = Rtotal
then I = V/R = 2.47A = total current in the circuit.

Then to get the current on the 14 ohm loopm i multiplied 2.47 by (14/17) . ( i think this is where I am erring, but can't see why this doesn't work??)

= 2.03A (wrong)
thanks for any help!

 

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you're making this too complicated.

the voltage between the two nodes must be the battery voltage.

so if you know the voltage across a resistor (or an Eq Res) you can find the current through it.


use I = V/R, where R is the equivalent resistance of the branch and V is the voltage across the branch.
 

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