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## Homework Statement

I am just looking for someone to verify that my approach is correct.

i(t) is the current through the capacitor and w(t) is the energy stored in the capacitor.

## Homework Equations

For a capacitor, the current through it can be related to the voltage drop across the capacitor:

[tex]i_c = C\frac{dv_c}{dt}[/tex]

where C is the capacitance (a constant in this case).

## The Attempt at a Solution

The source voltage is given (as function of time) pictorially in figure 1.2.21. From Kirchoff's voltage law, we know that [itex]v_c(t) = -v_{source}(t)[/itex] Hence we can find the slope [itex]dv_c/dt = -dv_{source}/dt[/itex].

From the figure, from t = -1 to t =0, the slope of the source voltage is 2, hence the capacitor voltage's slope is -2. So the current through the capacitor is -2*C from t = -1 to 0.