- #1
VinnyCee
- 489
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Find v1 and v2 in the circuit shown. Also calculate i1 and i2 and the power dissipated in the 12-ohm and 40-ohm resistors:
My work so far:
[tex]i_1\,=\,\frac{N1\,-\,N2}{12\Omega}[/tex]
[tex]i_2\,=\,\frac{N2\,-\,0}{40\Omega}[/tex]
[tex]i_3\,=\,\frac{N1\,-\,N2}{6\Omega}[/tex]
[tex]i_4\,=\,\frac{N2\,-\,0}{10\Omega}[/tex]
KCL at N2: [tex]i_1\,+\,i_3\,=\,i_4\,+\,i_2[/tex]
KVL for loop 1: [tex]15V\,+\,i_3(6\Omega)\,+\,i_4(10\Omega)\,=\,0[/tex]
KVL for loop 2: [tex]i_4(10\Omega)\,-\,i_2(40\Omega)\,=\,0[/tex]
I have no idea where to go from here. These things are so confusing! What would I do to get the i1 and i2?
I know that the voltage at N1 is -15V, but how do I solve the rest?
My work so far:
[tex]i_1\,=\,\frac{N1\,-\,N2}{12\Omega}[/tex]
[tex]i_2\,=\,\frac{N2\,-\,0}{40\Omega}[/tex]
[tex]i_3\,=\,\frac{N1\,-\,N2}{6\Omega}[/tex]
[tex]i_4\,=\,\frac{N2\,-\,0}{10\Omega}[/tex]
KCL at N2: [tex]i_1\,+\,i_3\,=\,i_4\,+\,i_2[/tex]
KVL for loop 1: [tex]15V\,+\,i_3(6\Omega)\,+\,i_4(10\Omega)\,=\,0[/tex]
KVL for loop 2: [tex]i_4(10\Omega)\,-\,i_2(40\Omega)\,=\,0[/tex]
I have no idea where to go from here. These things are so confusing! What would I do to get the i1 and i2?
I know that the voltage at N1 is -15V, but how do I solve the rest?
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