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Circular motion bug on tire

  1. Sep 28, 2011 #1
    1. The problem statement, all variables and given/known data
    At takeoff, a commercial jet has a speed of 60.0 m/s. Its tires have a diameter of
    0.850 m.
    (a) At how many rpm are the tires rotating?
    (b) What is the centripetal acceleration at the edge of the tire?
    (c) With what force must a determined 10-15 kg bacterium cling to the rim?
    (d) What is the ratio of this force to the bacterium’s weight?


    2. Relevant equations
    angular velocity = v/r
    centripetal acceleration = v^2/r


    3. The attempt at a solution

    I divided 60.0 m/s by .425 m to get (a). To get (b) I squared 60.0 m/s and divided it by .425 m. I am really stuck on (c). I am thinking the force it needs to cling to the rim is equal to the centripetal force. So, does that mean I just multiple it's mass by the centripetal acceleration? Any help would be appreciated.
     
  2. jcsd
  3. Sep 29, 2011 #2

    ehild

    User Avatar
    Homework Helper
    Gold Member

    Take care with the answer to (a). v/r is the angular velocity, not the revolutions per minute, rpm.
    (c): you are right, the centripetal force is centripetal acceleration multiplied by the mass and that force is needed to move together with the tyre.

    ehild
     
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