Circular Motion/Centripetal Forces

  • Thread starter Thread starter omgitsmonica
  • Start date Start date
  • Tags Tags
    Circular Forces
AI Thread Summary
A 2.1 kg mass on a 0.5 m string experiences a maximum tension of 80 N while being whirled in a horizontal circular path. The relevant equations for centripetal acceleration and force are discussed, leading to the calculation of maximum speed. By applying Newton's second law, the acceleration is determined to be 38.1 m/s², resulting in a maximum speed of approximately 4.36 m/s. The discussion highlights the importance of the horizontal orientation of the motion, noting that gravitational forces would alter the calculations if the motion were vertical. Understanding these dynamics is crucial for accurately determining forces in circular motion scenarios.
omgitsmonica
Messages
22
Reaction score
0

Homework Statement


A 2.1 kg mass is attached to the end of a .5m string. The system is whirled in a horizontal circular path. If the maximum tension that the string can withstand is 80N, what is the maximum speed in m/s of the mass if the string is not to break?


Homework Equations



Ac=v2/r


The Attempt at a Solution


I have no idea how to go about solving this. I don't know what mass has to do with anything...
 
Physics news on Phys.org
You have the right equation for a, just put it into Newton's second law.
 
F=ma, so 80N=2.1a so 38.1=a

Ac=v2/r, so 38.1=v^2/.5

So v^2=19.05, so v = 4.36

Is that right?
 
Yes

So the Fnet is the Ft and it is equal to mv^/r

But the key word in this questions is its horizantal. Do you know what would be diffirent if it wasnt horizantal?
 
I imagine it would be the acceleration, because the direction of motion would be changed. Or does that not matter, like trajectories?
 
If it is horizantal the only thing would be different is that gravity acting on the object that is spinning should also be factored in into the Fnet formula.

So at the top

Fc= Ft + Fg

Bottom

Fc= Ft-Fg
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top