Circular Motion Concepts: Understanding the Stability of Rotating Objects

AI Thread Summary
When a stone is swung on a string in a circular motion, it remains stable despite gravitational acceleration acting downward. The tension in the string and the force exerted by the hand create a balance of forces, including the centripetal force necessary for circular motion. A free-body diagram illustrates that gravitational force (mg) and tension (T) interact with the swinging force from the hand. The stone's position is not confined to the xy plane; it has a vertical displacement along the z-axis. This displacement, combined with the centripetal force, counteracts gravity, preventing the stone from falling.
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Homework Statement


how come that if I grab a stone and attach it to a string and then rotate it along the xy axis it won't fall even though there is acceleration from gravity in the z axis where no force is applied?


Homework Equations





The Attempt at a Solution


maybe its the fact that I am holding the string comes to play I don't know.
 
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Notice that if you perform such an experiment, you'll need to swing the string at an angle constantly. If your own hand is in a x-y motion, yes the stone would drop. But if you want to swing the stone above your hand, what you're actually doing is swinging with a x-y-z component force.

If you draw a free-body diagram, there should be mg acting on the stone, tension of string, T, and the swinging force provided by the hand that is in the opposite direction of the tension. After all forces resolve, there should be the centripetal force only.
 
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The stone isn't in the same xy plane as the point where you're holding it. It's somewhat lower, displaced along the z axis. The harder you swing the stone, the less that displacement will be, but it will never be zero. There will always be a component which, when multiplied against the centripetal force generated by the orbiting stone, will be enough to counteract the force of gravity on the stone.
 
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