Circular Motion Prac: Investigating Centripetal Force Relationships

AI Thread Summary
The experiment investigated the relationships between centripetal force, mass, and radius in circular motion. The initial findings suggested that the square of the period (T²) is proportional to the radius (R) and the moving mass (m_v), while being inversely proportional to the centripetal mass (m_c). Clarification was provided that the period is independent of the radius when angular speed is constant. The correct relationship derived from the forces involved indicates that T² = (4π²m_vR)/(g m_c). To further validate the results, plotting T² against (m_vR/m_c) should yield a directly proportional graph.
ellese
Messages
2
Reaction score
0
I recently completed an experiment about centripetal motion in which we attached a string to a weighed mass and passed the string through a glass tube, tying the free end to another weighed mass. We then moved the tube so the upper mass traced out circular motion and recorded the period of rotation. We then varied independently each of the masses and the radius of rotation.

On plotting the graphs, however, I wasn't able to clearly work out the relationship between the variables.

My best calculations are that

T squared is proporional to R
T squared is inversely proportional to the mass used to provide the centripetal force
T is proportional to the moving mass

I'm not sure of the equations I should be using to determine these relationships. Can anyone help?
 
Physics news on Phys.org
I don't really understand the experiment youre carrying out. The forces that are acting seem to be the centrifugal force: mw^2r, gravity:mg, and the tension in the string. Draw a fbd and try to work out a general expression for the forces on your system. The expression you get, you can try verifying it with your experimental results.
 
Sorry, let me rephrase the question.

Basically what I am trying to work out is how the radius is related to the period of an object undergoing circular motion with a constant centripetal force.

My experimental results don't seem to show any discernable relationship.
 
The force is constant. So then v=rw. T=\frac{2\pi r}{rw}. As you see, the radius cancels out, so the time period is independent of radius. This is only valid since the angular speed is constant.
 
The centripetal force that the moving mass, m_v, is experiencing is given by

F_c = m_c g

and it is also represented by

F_c = \frac{m_v v^2}{R}

while the speeed of the moving mass is

v = \frac{2 \pi R}{T}

this gives the relation

T^2 = \frac{4 \pi ^2 m_v R}{g m_c}

The square of the period is therefore directly proportional to m_v and R, and it is inversely proportional to m_c. So your approach is correct. As a further test you could calculate and plot the square of the period as a function of the values

\frac{m_v R}{m_c}

this graph should then be a directly proportional graph with a gradient of

\frac{4 \pi ^2}{g}

Just be sure to use values in your calculations that represent a single set of measurements.
 
Last edited:
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top