Circular Orbit / Practice Quiz #4, Question 27

AI Thread Summary
The discussion focuses on calculating the acceleration due to gravity at an altitude of 1.00 x 10^6 meters above Earth's surface, using the formula g = GM/r^2. Participants clarify that the mass of the object is not needed for the calculation, as the mass of the Earth (M) is the only variable required. It is emphasized that the radius used in the formula should include both the Earth's radius and the altitude of the object. The approach involves writing expressions for gravity at two different radii and using ratios to simplify the calculation. This method allows for determining the acceleration without needing to know the actual mass of the Earth or the gravitational constant.
gcombina
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Homework Statement

What is the acceleration due to gravity at an altitude of 1.00 x 10^6 above the Earth's surface, given that the radius of the Earth is 6.38 x 10^6 m?

Homework Equations


Using g = GMm/r^2
Fc = mv^2/r

The Attempt at a Solution


Fc = mv^2/r

How can I solve this equation if I am missing m and v?
 
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The only force acting upon the object in this example is the force of Earth's gravity. You only need to use the equation F=GMm/r^2...remember F=ma, which means that acceleration=G*M/r^2 and mass =m. F=m*a=m*(GM/r^2)
 
gcombina said:

Homework Statement

What is the acceleration due to gravity at an altitude of 1.00 x 10^6 above the Earth's surface, given that the radius of the Earth is 6.38 x 10^6 m?

Homework Equations


Using g = GMm/r^2
Fc = mv^2/r

The Attempt at a Solution


Fc = mv^2/r

How can I solve this equation if I am missing m and v?

Write the 2 equations, one at the surface of the Earth where you know the value of g, and the other at altitude. You should be able to cancel a lot of things out... :-)
 
MattHorbacz said:
The only force acting upon the object in this example is the force of Earth's gravity. You only need to use the equation F=GMm/r^2...remember F=ma, which means that acceleration=G*M/r^2 and mass =m. F=m*a=m*(GM/r^2)
and mass =m. F=m*a=m*(GM/r^2)[/QUOTE]

I don't understand this last part. Are you saying
m= m
F = ma = m * (GMr^2)

where did you get the mass from? I thought the equation for acceleration is G*M/r^2
 
If the formula is a= GM/R^2

then i only need the value of M
 
gcombina said:
If the formula is a= GM/R^2

then i only need the value of M
yes exactly...M in this case is the mass of the earth...it appears that they want you to look it up yourself...it happens to be 5.972*10^24 kg

ALSO! don't forget that your radius is actually radius of Earth + objects distance from earth
 
If you have the acceleration due to gravity at one radius (like the surface of the Earth), then you can find the acceleration due to gravity at another radius using ratios. No need to know the actual mass of the Earth or the value of G.

Write the expression for the acceleration due to gravity for both locations using appropriate variables (so R1 and g for one, R2 and a for the other). Then make a ratio of the equations. All the common variables will cancel.
 
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