rash219
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Clarification about friction equation !
Suppose there is an object on the top of a ramp at a rest would these equation/s be correct to preform calculations considering friction applies
\SigmaF_y = n - (m * g * Cos\Theta) = 0
\SigmaF_x = (m * g * Sin\Theta) - (\mu_s * n) = 0
Suppose there is an object on the top of a ramp was sliding downwards would these equation/s be correct to preform calculations considering friction applies
\SigmaF_y = n - (m * g * Cos\Theta) = 0
\SigmaF_x = (m * g * Sin\Theta) - (\mu_s * n) = (m * a) or
\SigmaF_x = (m * g * Sin\Theta) - (\mu_k * n) = (m * a)
Note : (\mu_k * n) would be located at (\mu_s * n)
http://img40.imagevenue.com/loc876/th_28739_dig_122_876lo.jpg
My Question is are these formulas correctly represented so that i could solve any question that involves static and kinetic friction
Homework Statement
Suppose there is an object on the top of a ramp at a rest would these equation/s be correct to preform calculations considering friction applies
\SigmaF_y = n - (m * g * Cos\Theta) = 0
\SigmaF_x = (m * g * Sin\Theta) - (\mu_s * n) = 0
Suppose there is an object on the top of a ramp was sliding downwards would these equation/s be correct to preform calculations considering friction applies
\SigmaF_y = n - (m * g * Cos\Theta) = 0
\SigmaF_x = (m * g * Sin\Theta) - (\mu_s * n) = (m * a) or
\SigmaF_x = (m * g * Sin\Theta) - (\mu_k * n) = (m * a)
Note : (\mu_k * n) would be located at (\mu_s * n)
http://img40.imagevenue.com/loc876/th_28739_dig_122_876lo.jpg
My Question is are these formulas correctly represented so that i could solve any question that involves static and kinetic friction
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