Classical electrodynamics -Good conductor

cowrebellion
Messages
6
Reaction score
0

Homework Statement


The question given is an electromagnetic wave incident on a vacuum metal interface. The wave is incident normally. We're given that the metal is a good conductor i.e. \omega \tau <<1 where \tau is the collision time of the metal and omega is the angular frequency. The metal is also non-magnetic and the conductivity is of the order of 10^8 Siemens per metre

The first part is easy enough it's just to show that T the transmissivity is equal to 2/n where n is the real part of N the refractive index.

The part that has me stumped is to find the value of \omega so that the fraction of incident power deposited beyond a depth d is maximised


Homework Equations



I think the relevant equation is the poynting vector.

I'm taking the time averaged poynting vector for a wave in vacuum as S_{avg} = \frac{1}{2} \sqrt{\frac{\epsilon}{\mu}} E_{i}^{2} and inside the metal I assume the formS_{avg} = \frac{1}{4} \sigma_{0} \delta E_{t}^{2} e^{\frac{-2 z}{\delta}

Where delta is given as\sqrt{\frac{2}{\mu \omega \sigma_{0}}}

I'm also takingn=\frac{c}{\omega \delta}

The Attempt at a Solution


I started by saying that since the time averaged poynting vectors is independent of x and y in both case we can say
\int S_{avg} dA=S_{avg} A

Using this I divided the power incident on the surface by the power incident on hte same area but at a distance d below the surface to obtain\frac{\delta \sigma_{0}}{2}\sqrt{\frac{\mu}{\epsilon}}\frac{E_{t}}{E_{i}}\frac{E_{t}}{E_{i}}e^{\frac{-2 d}{\delta}}but with this I differentiate w.r.t. omega and I can't obtain an answer? It's been bugging me for a while so I hope someone can help me out. Hope the format of the question is ok It's my first time posting here. =D

edit: I forgot to say that I replaced {E_{t}/E_{i}}^2 with 2/n I tried changing the latex code but it won't edit for some reason.
 
Last edited:
Physics news on Phys.org
You have already assumed that the field decays exponentially on the scale of the skin depth

\delta=\sqrt{\frac{2}{\mu \omega \sigma_{0}}}

But this already gives you the answer: to maximize power deposition beyond d, choose a frequency to make the skin depth greater than d.
 
That makes sense but the question asks for a specific value of the frequency. Initially I thought I'd obtain an equation of the form \omega e^{-\omega} which has a definite maximum value.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top