1. The problem statement, all variables and given/known data I was looking into taking the Calculus CLEP Exam and came across this practice problem: Derive the general solution to the following differential equation: y' = sin x. A. sin y + cos x = C B. tan y = C C. sin y - cos x = C D. cos x = C E. cos x - sin y = C 3. The attempt at a solution The first thing I thought was that the question was asking for me to integrate y'=sin X. If y' = sin X, then y = -cos x + C. I didn't know what they wanted me to do so I simply set this equal to zero, so -cos x + C = 0 and therefore cos X=C. However, D is not the correct answer. So, my question is: what is it that the question is asking me to do when it says it wants a "general solution to ...[a] differential equation"?