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Homework Statement
I was looking into taking the Calculus CLEP Exam and came across this practice problem:
Derive the general solution to the following differential equation: y' = sin x.
A. sin y + cos x = C
B. tan y = C
C. sin y - cos x = C
D. cos x = C
E. cos x - sin y = C
The Attempt at a Solution
The first thing I thought was that the question was asking for me to integrate y'=sin X. If y' = sin X, then y = -cos x + C. I didn't know what they wanted me to do so I simply set this equal to zero, so -cos x + C = 0 and therefore cos X=C. However, D is not the correct answer. So, my question is: what is it that the question is asking me to do when it says it wants a "general solution to ...[a] differential equation"?