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Coefficient of friction - bullet traveling through a block

  • Thread starter mybrohshi5
  • Start date
  • #1
365
0

Homework Statement



A bullet with a mass of 7.00 g is fired horizontally with a speed of 420 m/s, into a wooden block with mass of 0.820 kg, initially at rest on a level surface. The bullet passes through the block and emerges with its speed reduced to 130 m/s. The block slides a distance of 47.0 cm along the surface from its initial position.

What is the coefficient of kinetic friction between block and surface?

Homework Equations



vf2=vi2+2ad

F=ma

uk = fk/n

The Attempt at a Solution



I found the acceleration of the bullet

1302=4202+2a(.47)

a= -169680.8

i then thought i could find the force and then divide that by the normal force to get uk but my number was very large (141) :(

Can anyone help me on this one please.

Thank you :)
 

Answers and Replies

  • #2
Filip Larsen
Gold Member
1,256
183
Think about if you perhaps can use conservation of momentum to analyze your problem.
 
  • #3
365
0
Got it. That worked perfectly. Thank you i appreciate it :)
 

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