Coefficient of friction problem

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SUMMARY

The coefficient of friction for a body of mass 10 kg on a rough horizontal surface was determined through two scenarios involving different accelerations. Initially, the body accelerated at 5 m/s², and upon doubling the horizontal force, the acceleration increased to 18 m/s². The calculations using the equations of motion and friction led to the conclusion that the coefficient of friction is 0.4, corresponding to option C.

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  • Understanding of Newton's laws of motion
  • Knowledge of frictional forces and coefficients
  • Ability to solve equations involving forces and acceleration
  • Familiarity with basic algebra for solving equations
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  • Learn about Newton's second law of motion in detail
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kranav
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Homework Statement



a body of mass 10 kg lies on a rough horizontal surface with an acceleration of 5 m/s and when the horizontal force us doubled , it gets an acceleration of 18 m/s^2. Then the coefficient of friction between the body and the horizontal surface is:

A) 0.2 B) 0.8 C) 0.4 D) 0.6


Homework Equations


fnet = f - umg = ma1 1st case
Fnet = F - umg = ma2 2nd case

The Attempt at a Solution


I tried to solve it but u comes out to be zero.
 
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kranav said:
fnet = f - umg = ma1 1st case
Fnet = F - umg = ma2 2nd case
This looks good. (How do f and F relate?)

The Attempt at a Solution


I tried to solve it but u comes out to be zero.
Try it one more time.
 
Doc Al said:
This looks good. (How do f and F relate?)


Try it one more time.


thanks! got the answer!
 

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