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1. The problem statement, all variables and given/known data

Ms. Boylan on her 1750-kg cart is traveling at a constant speed of 8.5-m/s on a wet, straight, and slippery road. A mindless student steps out in from of the cart. The wheels lock and she begins skidding and slides to a halt in 12.0-m. What is the coefficient of sliding friction between the tires and the slippery road?

2. Relevant equations

vf^2 = vi^2 + 2ad

a = (Fapplied - Fopposed) / mass

u = Ffriction / weight

3. The attempt at a solution

Her acceleration is found with:

(0)^2 = (8.5)^2 + 2(a)(12)

a = -3.01 m/s^2

So, -3.01 equals applied force minus Ffriction over 1750.

Then I get stuck. If I could just figure that out, I could divide it by (1750 * 9.80) to get the coefficient. Thanks for your help.

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# Homework Help: Coefficient of Sliding Friction

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