Golf Cart Questions 1. The problem statement, all variables and given/known data Ms. Boylan on her 1750-kg cart is traveling at a constant speed of 8.5-m/s on a wet, straight, and slippery road. A mindless student steps out in from of the cart. The wheels lock and she begins skidding and slides to a halt in 12.0-m. What is the coefficient of sliding friction between the tires and the slippery road? 2. Relevant equations vf^2 = vi^2 + 2ad a = (Fapplied - Fopposed) / mass u = Ffriction / weight 3. The attempt at a solution Her acceleration is found with: (0)^2 = (8.5)^2 + 2(a)(12) a = -3.01 m/s^2 So, -3.01 equals applied force minus Ffriction over 1750. Then I get stuck. If I could just figure that out, I could divide it by (1750 * 9.80) to get the coefficient. Thanks for your help.