Engineering Collector Current through BJT Circuit

AI Thread Summary
The discussion revolves around calculating the current through R3 (IL) in a BJT circuit. The user initially calculated IL as 4.15mA, but their tutor indicated the correct value is 4.3mA. The discrepancy arises from the tutor's assumption that the emitter current (Ie) equals the load current (IL) and that the base current (Ib) is negligible. This assumption affects the voltage drop calculations, leading to the different results. Ultimately, understanding these assumptions clarifies the reasoning behind the correct answer.
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Homework Statement



Consider the following circuit
http://img109.imageshack.us/img109/80/circuit1.jpg

IL, current through R3 (unknown resistance must be found)


Homework Equations


Vth=(Vcc/Rtotal)*R1 (V tThevenin)

Rth=R1//R2 (R Thevenin)

Vbe= 0.7 volts (silicon diode)
Beta (transistor constant)=100
Vcc=10v
IL=Beta*Ib
Ie=Ib + IL

The Attempt at a Solution



I used the following Equation to try and obtain an answer.

Vcc= (Ib*Rth)+ (Ie*R4) + Vbe + Vth

Vth=5v
Rth=2.5k Ohms

Substituting gives:

10=(IL/Beta)*(2.5k) + 1000*(IL*((Beta +1)/Beta)) + 0.7 + 5

This yields an answer of IL=4.15mA.

My tutor said this is a wrong answer, the correct one is 4.3mA
What is wrong in my reasoning/Working?
 
Last edited by a moderator:
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I like your answer better.

The tutor has just taken 0.7 V from the 5 V at the center of the two 5K resistors and said this must be the voltage across the emitter resistor.

But the base current pulls this voltage down a little and that makes the difference between your answers.
 
THanks,

I just realized what he did,


He assumed Ie=IL and Ib=0 since it is very small.
 

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