Collimating light from Optical fibre problem

XCBRA
Messages
18
Reaction score
0

Homework Statement



A thin lens of focal length f is used to collimate the light emerging from two different optical fibres.
When used with a first fibre of small core diameter and numerical aperture NA it acheives a diffraction limited divergence of θ1 for the collumated beam. Find the separation u between the lens and the fibre that provides the best collimation. Find θ1 and the diameter D of the collumated beam immediately behind the lens.

When used with a second fibre of a large core diameter d but the same numerical aperture, the beam diverges much faster than it did using the first fibre. Calculate this larger divergence angle 2 as a function of f and d


Homework Equations



NA = sin(θ1)

1/u+1/v=1/f

The Attempt at a Solution



I am not entirely sure how to approach this problem as it is not a point source. I would like to say that:

for best collimation u = f -- from lens equation
and then

D=f tan(θ1) ≈ fθ1 ≈ f NA -- from trigonometry

however I am not sure if this is correct. Any hints on how to approach this question would be greatly appreciated. Many thanks
 
Physics news on Phys.org
wow, so difficult to me!
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top