Collision of particle with plate

utkarshakash
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Homework Statement


A uniform square plate of mass m and side a can freely rotate about a vertical axis passing through one edge. It is initially at rest. A particle of mass m is moving horizontally and perpendicular to the plane of the plate with velocity u. The particle collides with the plate elastically at the centre of the plate. Find the angular velocity of the plate just after collision.


The Attempt at a Solution



Applying conservation of angular momentum about the vertical axis,

[itex]mua/2 = mu'a/2 + \dfrac{ma^2}{12} \omega[/itex]

Since the particle elastically collides with the center of plate,

[itex]\omega \dfrac{a}{2} - u' = u[/itex]

where u' is velocity of particle after collision.

Doing this way gives me wrong answer! :frown: Any ideas where I'm going wrong?
 
on Phys.org
utkarshakash said:

Homework Statement


A uniform square plate of mass m and side a can freely rotate about a vertical axis passing through one edge. It is initially at rest. A particle of mass m is moving horizontally and perpendicular to the plane of the plate with velocity u. The particle collides with the plate elastically at the centre of the plate. Find the angular velocity of the plate just after collision.


The Attempt at a Solution



Applying conservation of angular momentum about the vertical axis,

[itex]mua/2 = mu'a/2 + \dfrac{ma^2}{12} \omega[/itex]

Since the particle elastically collides with the center of plate,

[itex]\omega \dfrac{a}{2} - u' = u[/itex]

where u' is velocity of particle after collision.

Doing this way gives me wrong answer! :frown: Any ideas where I'm going wrong?

Hi utkarshakash!

The moment of inertia seems to be incorrect.
 
Pranav-Arora said:
Hi utkarshakash!

The moment of inertia seems to be incorrect.

Should it be (ma^2)/3?
 
utkarshakash said:
Should it be (ma^2)/3?

Yes, looks correct to me. :)
 

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