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Collisions on 2Dimensions.

  1. Sep 26, 2007 #1
    A 5.00 kg Ball A moving at 12.0 m/s collides with a stationary 4.00 kg Ball B. After
    the collision, Ball A moves off at an angle of 38.0º right of its original direction. Ball B 52.0º left of Ball A's original direction. After the collision, what is the momentum
    of Ball A?


    P1 + P2 = P1' + P2'
    60 + 0 = P1' + P2'

    After this I have no idea where to go. We would need a velocity however there isnt one given.

    I'm assuming a vector diagram would be useful, but Im not too sure what that would look like.
     
  2. jcsd
  3. Sep 26, 2007 #2

    hage567

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    You must break up the momentum into the x and y components, and sum up in each direction. Draw a diagram to keep track of everything.
     
  4. Sep 27, 2007 #3
    I dont have the hypotenuse to be able to do that. The only thing I could think of would be x =(60-y) and y=(60-x)
     
  5. Sep 27, 2007 #4
    Ok so I also asked this question on Yahoo answers, and some person gave me this:

    Now I have never seen anything alike this taught to me. Does this have any truth to it?

    I was also given this which seems more.... legit

     
  6. Sep 27, 2007 #5
    You don't need the hypotenuse to break into components. You have the angle given after the impact, use trigonometry.

    [EDIT]

    The first response is completely off. The second one seems right to me as well.
     
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