Commutative free particle time evolution

Click For Summary

Homework Help Overview

The discussion revolves around the time evolution of a free particle in quantum mechanics, specifically focusing on the variance and expectation values related to the particle's position.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand the time evolution of variance and how it relates to quantum mechanics. Some are exploring the mathematical formulation of the Schrödinger equation and its implications for the problem. Others are questioning the translation of statistical concepts into the quantum framework.

Discussion Status

There are various lines of reasoning being explored, with some participants attempting to derive expressions for expectation values and variances. However, there is a lack of consensus on the approach to take, and confusion remains regarding the mathematical steps involved.

Contextual Notes

Participants express uncertainty about the initial steps required to tackle the problem, particularly regarding the integration of the Schrödinger equation and the calculation of expectation values. There are indications of imposed homework constraints that limit the scope of discussion.

chaotic
Messages
18
Reaction score
0

Homework Statement



http://img853.imageshack.us/img853/2532/70224197.png

Homework Equations



i know schrödingher eq. and basic quantum formula

The Attempt at a Solution



i showed that the equality at the first question but i can not start from (a) part. how and where am i supposed to start for (a) part of question?
 
Last edited by a moderator:
Physics news on Phys.org
i even don't know what is the time evoluation of varience? what is that?
 
Forget quantum mechanics for a second. From basic statistics, if x is a random variable, its variance is ##\sigma^2 = E[(x-\bar{x})^2]##, where ##\bar{x}=E(x)##. Now how does this translate into quantum mechanics? It should be clear how the first part of the problem then applies to solving (a).
 
thank you for your answer. now i am trying that

[itex]\frac{dψ}{dt}[/itex] = [itex]\frac{iħ}{2m}[/itex] d2ψ/dx2

after that i find that; (i send dt to right side)

ψ = ∫ [itex]\frac{iħ}{2m}[/itex] d2ψ/dx2 dt

but i don't know how can i take the integral of right side?

after that i will use the <x> = ∫ψ* x ψ

is that true?
 
I have no idea what you're doing.
 
me too. I am very confused. can you just tell me how can i find <x(t)> and <x(t)^2>
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
9
Views
3K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
8
Views
2K