Commutativity and Associativity of Jordan Product

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SUMMARY

The Jordan product of two n x n matrices A and B, defined as (AB + BA)/2, is commutative but not associative. To demonstrate commutativity, one must show that A*B = B*A, while for associativity, it is necessary to prove that A*(B*C) ≠ (A*B)*C. The discussion provides a clear method for expanding these expressions to verify the properties of the Jordan product.

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Homework Statement


A and B are n x n matrices, so their Jordan Product is (AB + BA)/2. Show that this product is commutative but not associative.


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The Attempt at a Solution


I understand the logic behind the answer, but I don't know how to show it. Where would I start?
 
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/edit: deleted answer.

For associativity, just write out A*B and B*A and expand. For commutivity, write out A*(B*C) and (A*B)*C, and if what you get when you expand the two things is not the same, then you have shown what you wanted.
 
Last edited:
JeSuisConf said:
/edit: deleted answer.

For associativity, just write out A*B and B*A and expand. For commutivity, write out A*(B*C) and (A*B)*C, and if what you get when you expand the two things is not the same, then you have shown what you wanted.
Thank you so much for the help. I figured out this question and the other Jordan Product questions from your advice.
 

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