Comparing Currents: Two Wire Comparison Homework

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The discussion focuses on comparing the currents in two wires with different drift speed profiles. Wire 1 has a drift speed that increases linearly from the circumference to the center, while wire 2 has a constant drift speed. To find the ratio of currents, the equation I=nqAVd is used, simplifying to I2/I1 = Vd2/Vd1 since charge density and cross-sectional area are constant. The current for wire 1 requires integration due to its variable drift speed, while wire 2's current is straightforward. The conversation concludes with an acknowledgment of understanding the integration process needed for wire 1.
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Homework Statement


The diagram shows two wires; wire 1 and wire 2. The charge carriers in wire 1 (of circular cross section and radius R) have a drift speed down the wire that is not constant across the wire. Instead, the drift speed rises linearly from zero at the circumference (r=R) to at the center (r = 0), according to vd1(r)=Vo(1-(r/R)).The second wire (wire 2) has the same radius, the same density of charge carriers and a constant drift speed given by vd1(r)= fVo. Evaluate the ratio of the current carried by wire 2 to the current carried by wire 1, when f = 0.490.

Homework Equations


I=nqAV_{d}

\frac{qnAV_{d2}}{qnAV_{d1}}

The Attempt at a Solution


So since q,n,A are the same they cancel leaving:
\frac{I_{2}}{I_{1}}= \frac{V_{d2}}{V_{d1}}
I need to find vd now.
 

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To find current in first wire you need to integrate. Sice speed is constant at fixed r you should write: dI=nqv(r)2\pi rdr and then integrate.

Hope you understand why, else ask.
 
got it thanks. Yes I know why
 
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