Comparing momentum and impulse of sleds

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SUMMARY

The discussion centers on comparing the momentum of two sleds, where one sled has a mass of 2m and the other has a mass of m. The momentum of the sled with mass 2m is derived using the formula p=mv, leading to the conclusion that its momentum is √2 times greater than that of the sled with mass m, given that both sleds have the same kinetic energy at the finish line. The relationship between kinetic energy and momentum is established through the equation Kinetic energy = 1/2 * m * v^2, which can be manipulated to relate momentum and mass effectively.

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  • Understanding of momentum (p=mv)
  • Knowledge of kinetic energy (K.E. = 1/2 * m * v^2)
  • Familiarity with calculus concepts (sigmaF=dp/dt)
  • Basic algebra for manipulating equations
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  • Investigate the implications of mass differences on momentum and energy conservation.
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marcuss
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1. The one sled has a mass of 2m and the other sled has a mass of m show that sled one with mass 2m has a momentum of root2 compared to the sled with mass m.

The only formulas that i could think to use were p=mv and sigmaF=dp/dt and i can't seem to find a way to relate them to get an answer so any help would be nice ty.
 
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marcuss said:
1. The one sled has a mass of 2m and the other sled has a mass of m show that sled one with mass 2m has a momentum of root2 compared to the sled with mass m.

The only formulas that i could think to use were p=mv and sigmaF=dp/dt and i can't seem to find a way to relate them to get an answer so any help would be nice ty.


Was that the entire problem, or were you told anything else about the sleds? For example were their kinetic energies related somehow, or did they tell you something about their motion?
 
their kinetic energies were the same at the finish line
 
Kinetic energy = 1/2*m*v^2 = 1/2*(m^2*v^2)/m = 1/2*p^2/m
Use this relation between energy and momentum.
 

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