Complex Analysis- Singularities

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Homework Statement


Let f be analytic at the complex plane excapt for z= -1 and z=3 which are simple poles of f.

Let \Sigma_{-\infty}^{-1} a_{n}(z-2)^{n} be the Laurent series of f.
In part A I've found that the series converges at 1<|z-2|<3 .
B is: Find the coeefficients a_{n} of the given Laurent series.
Hint: Look at g(z) = (z+1)(z-3)f(z)


Homework Equations


The Attempt at a Solution


We know that g(z) has no poles or singularities whatsoever. So Laurent series of g is actually a Taylor series... But how can we find from this data the given coeefficients?

Thanks in advance
 
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Are you sure that's a correct Laurent series for f(z)? Doesn't it have an essential singularity at z=2?
 
I'm sure indeed...I had no typos in this one... But the an's can be also zero or something...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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