Complex number multiple choice

AI Thread Summary
The discussion centers on the equation Z = 1/(z conjugate) and explores the implications for the complex number z, represented as a + bi. It is established that a² + b² = 1 indicates that z lies on the unit circle in the complex plane, meaning it is not necessarily purely real or imaginary. The condition for z to be real is that b must equal zero, but this is not a requirement for all cases. The conclusion drawn is that z can be any complex number on the unit circle, which does not fit the provided multiple-choice options. Overall, the key takeaway is that z represents a complex number with a magnitude of one, regardless of its angle in polar coordinates.
alijan kk
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Homework Statement


If Z= (1)/(z conjugate) then Z : ?

Homework Equations

The Attempt at a Solution


let z= a+bi
the z conjugate= a-bi

(a+bi)=(1)/(a-bi)

(a+bi)(a-bi)=1

a2+b2=1

does it tell from this expresssion that the complex number is a pure real ?
 
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alijan kk said:
does it tell from this expresssion that the complex number is a pure real ?
What is the condition on ##a## and ##b## for ##Z## to be real?
 
No. What does a2 + b2 = 1 mean geometrically? Think of a graph in the complex plane.
 
DrClaude said:
What is the condition on ##a## and ##b## for ##Z## to be real?
b should be zero if the complex number is pure rule
can we put b= 0
 
alijan kk said:
b should be zero if the complex number is pure rule
can we put b= 0
We can set b = 0, but we don't have to, so this is not the answer to the problem.
 
DrClaude said:
We can set b = 0, but we don't have to, so this is not the answer to the problem.
so this a wrong question in my book ?
 
alijan kk said:
so this a wrong question in my book ?
No, the question asks about what you can say about a number for which ##z = \bar{z}^{-1}##. See @mjc123's post above for a hint.
 
mjc123 said:
No. What does a2 + b2 = 1 mean geometrically? Think of a graph in the complex plane.
a unit circle ,
 
the inverse is 1/a2+b2 of a2+y2 and that is a real number ! am i right ?
 
  • #10
##a^2+b^2## will always be real. That doesn't tell you anything about ##z##.
 
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  • #11
DrClaude said:
##a^2+b^2## will always be real. That doesn't tell you anything about ##z##.

options are:
z is purely imaginary
z is any complex number
z is real
none of these
 
  • #12
alijan kk said:
options are:
z is purely imaginary
z is any complex number
z is real
none of these

if it doesn't tell about z ,, then should the answer be (none of these)
 
  • #13
It does tell you something about z, but not one of those options. You got it in post #8 - a unit circle. More specifically, z is any complex number represented by a point in the complex plane that lies on the circumference of a unit circle centered on the origin.
Are you familiar with the polar notation for complex numbers: z = re, where r2 = a2+b2 and tanθ = b/a?
Then z* = re-iθ and 1/z* = (1/r)e
So z = 1/z* for any number for which r = 1, for any value of θ.
 
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