Yeah that last post was an eye-sore. Save the msn talk for txt msgs
More simply, try factorising.
Using the difference of two cubes:
a^3-b^3=(a-b)(a^2+ab+b^2)
So, z^3-1=(z-1)(z^2+z+1)=0
Now you have two factors. A linear factor that gives z=1, and a quadratic that has unreal solutions. Solving this quadratic for z will give you the two imaginary roots of z^3=1 and if you know how to plot complex numbers on an argand diagram, then it should be easy from there.
p.s. all 3 solutions will lie on a circle of unit radius on the argand diagram.
EDIT: didn't read the whole question.
ok so to show the points lie on an equilateral triangle, are you aware that if you multiply a vector on the argand diagram by cis\theta, it will rotate the vector \theta in the anti-clockwise direction?
If you don't understand what I just said, then just show that the distance between all the solutions are equal, thus creating an equilateral triangle.