Component vector method for resultant force

AI Thread Summary
To find the resultant force using the component vector method, the forces need to be broken down into their x and y components. The 60 lb force on the x-axis contributes only to the x-component, while the 30 lb force at 120 degrees must be resolved into both x and y components using cosine and sine functions, respectively. The user expressed confusion about setting up the components correctly and indicated a preference for the parallelogram method. Guidance was provided on using cosine to find the x-component and sine for the y-component. The user plans to return for confirmation of their solution once they apply this method.
argentnox
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Homework Statement



An object has two ropes attached. One is on the x-axis (positive) with a 60 lb force. One is 120* (Quadrant II) from the first rope with a 30 lb force. I have to find the resultant force and angle using the component vector method of addition NOT the parallelogram method.

Homework Equations



Fa + Fb = R

The Attempt at a Solution



I set up a table of components, but I am not sure if they are correct. I am just really confused as to how to approach this problem. I know how to do it using the parallelogram method, but it seems like some important piece of information is missing for doing it using the component vector method.

A=30 lb
B= 60 lb

Angle A=120*
Angle B=0*

Ax = ??
Bx = 60 lb

Ay = ??
By = 0
 
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welcome to pf!

hi argentnox! welcome to pf!

(try using the X2 icon just above the Reply box :wink:)

to find the component in a direction, always multiply by cos of the angle to that direction :smile:
 
Thank you, I will try that and see how I do. If it is okay, I will probably come back to make sure I got the correct answer. I figure if I got the answer correct, I must have done the work correctly. ;)
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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