Composition of endomorphisms have same eigenvalues

Tmaker
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Homework Statement



For two endomorphisms ψ and φ on a vector space V over a field K, show that ψφ and φψ have the same eigenvalues. "Hint: consider the cases λ=0 and λ≠0 separately."



The Attempt at a Solution



I know that similar endomorphisms (φ and ψφ(ψ^-1)) have the same eigenvalues, so I have tried manipulating that expression with various choices for φ and ψ, but no luck. Other than that I just need a little help getting started
 
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if this is a linear? homomorphism and the values commute in a field...

[edit] working on problem, i will assume not linear...

[/2 edit] okay i see, you think will need the fact that the inverse maps have inverse eigenvalues...
 
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hint: for λ ≠ 0, let v be an eigenvector of φψ, and consider ψφψ(v).

this argument doesn't work if the eigenvalue is 0 (why?).

all is not lost, however. note if 0 is an eigenvalue of φψ, this means φψ is singular.

all you need to do is show that ψφ is likewise singular (hint: determinants).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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